8462/1H June 2022

8  ​​​​ This question is about acids and alkalis.

8-1  ​​​​ Explain why the pH of an acid depends on:

The​​ strength of the acid

The​​ concentration of the acid.

[4 marks]

ANSWER

Rule of Thumb

pH depends on H+​​ ion concentration​​ i.e.​​ the higher the concentration of H+​​ ions,​​ the lower the pH​​ value

The strength of the acid

The stronger an acid,​​ the greater the​​ ionization​​ / dissociation (in aqueous solution)​​ so​​ the stronger the acid​​ and hence​​ lower the pH​​ value.

The concentration of the acid

The higher the concentration of an acid,​​ the more acid / solute in the same volume of solution​​ so​​ higher the concentration of the acid​​ and hence​​ lower the pH.

8-2  ​​​​ A student titrated 25.00 cm3 of hydrochloric acid with 0.100 mol/dm3 barium hydroxide solution.

Table 2 shows the results

Table 2

The​​ student​​ calculated​​ the​​ volume​​ of​​ barium​​ hydroxide​​ solution​​ to​​ be​​ used​​ in​​ the titration calculation as 23.50 cm3.

Explain​​ why​​ the​​ student​​ used​​ a​​ volume​​ of​​ 23.50​​ cm3​​ of​​ barium​​ hydroxide​​ solution​​ in the titration calculation.

[2​​ marks]

ANSWER

The mean of titration numbers 2 to 5 values is​​ calculated because​​ 23.90 (cm3) is an anomalous result.

8-3  ​​ ​​​​ 25.00 cm3 of the hydrochloric acid reacted with 23.50 cm3 of the 0.100 mol/dm3 barium hydroxide solution.

The equation for the reaction is:

2 HCl(aq) + Ba(OH)2(aq) → BaCl2(aq) + 2 H2O(l)

Calculate the concentration of the hydrochloric acid in mol/dm3.

[4 marks]

ANSWER

Step1: Calculating Moles of​​ barium hydroxide​​ solution,

moles=conc.moldm3×volume(dm3)

moles of barium hydroxide =0.100×23.501000

 

moles ofbarium hydroxide =0.00235mol

Step 2:​​ Now seeing the balanced equation, we need to identify molar ratio

 

HCl: ​​ Ba(OH)2​​ =​​ 2:1

Therefore, moles of​​ HCl​​ is​​ =2×0.00235mol

 

moles of HCl is =0.00470 mol

 

=0.00470251000

 

 

Another student titrated sulfuric acid with barium hydroxide solution. The equation for the reaction is:

H2SO4​​ (aq) +​​ Ba (OH)2(aq) → BaSO4(s) + 2 H2O(l)

The student measured the electrical conductivity of the mixture during the titration. The better a conductor, the higher the electrical conductivity value.

Figure 10 shows the results.

Figure 10

8-4  ​​​​ Explain why the electrical conductivity of the mixture was zero when the sulfuric acid had just been​​ neutralized.

Use the equation for the reaction. Refer to ions in your answer.

Marks]

ANSWER

There are no ions that are free to move​​ because barium sulfate is​​ insoluble​​ solid ​​ and​​ hydrogen ions have reacted with hydroxide ions to produce water.

8-5  ​​​​ The student then added a further 10 cm3 of barium hydroxide solution. The electrical conductivity of the mixture increased.

Give one reason why.

[1 mark]

ANSWER

The mixture now​​ contains barium ions and hydroxide​​ ions which​​ are​​ free to move.