WCH11 October 2022

6​​ The partial oxidation of butane in the presence of a catalyst has been investigated as a possible source of hydrogen.

C4H10(g)​​ + 2O2(g)​​ → 4CO(g)​​ + 5H2(g)

(a) What is the most significant hazard associated with the pollutant CO(g)?

(1)

A it is a major contributor to the formation of acid rain

B it strongly absorbs infrared radiation

C it is toxic at low concentrations

D it is the main cause of ozone layer depletion

ANSWER

C​​ -​​ it is toxic at low concentrations

Analysis of Option/Explanation

Carbon monoxide is harmful because it binds to hemoglobin in the blood, reducing the ability of blood to carry oxygen. This interferes with oxygen delivery to the body's organs. The most common effects of CO exposure are fatigue, headaches, confusion, and dizziness due to inadequate oxygen delivery to the brain. Hence, option “C” reflects the most significant hazard.

(b) A mixture of 40cm3​​ of butane and 20cm3​​ of oxygen reacts in a sealed system to form carbon monoxide and hydrogen.

What is the total volume of gas in the system at the end of the reaction, in cm3?

(1)

A 30

B 60

C 90

D 120

ANSWER

D 120

Analysis of Option/Explanation

In order to understand the question first of all we look into balanced equation and identify moles, so we get as under;

C4H10​​ + 2O2→4CO2​​ + 5H2O

1 mole2 moles4 moles5 moles

When comparing butane and oxygen, it is clear that 1 mole of butane react with 2 moles of oxygen, therefore as per given volume in the question, 20cm3​​ of oxygen reacts with10 moles of butane and so the excess volume of butane remaining (unreacted) is​​ 30cm3​​ i.e.(40cm3-10cm3).

Since oxygen is the limiting reactant therefore we will compare the produced gasses moles with oxygen (limiting reactant), therefore;

2 moles of Oxygen produces 4 moles of CO2, hence for 20 cm3 of oxygen produces​​ 40cm3​​ of CO2.

Similarly, 2 moles of oxygen produces 5 moles of water, hence for 20 cm3 of oxygen produces​​ 50 cm3=52×20cm3

Therefore, making a total of volume of gasses at the end of reaction=(30+40+20)cm3

=120cm3, hence,​​ Option D​​ is the correct answer.