12 A mass of 4.08g of hydrated copper (II) sulfate, CuSO4∙5H2O, was dissolved in deionized water to form 250cm3 of solution. What is the concentration of the copper (II) sulfate solution formed, in mol dm–3?
A 0.0163
B 0.0256
C 0.0654
D 0.102
ANSWER
C 0.0654
Analysis of Option/Explanation
Step 1: finding moles by ratio method
Mr of CuSO4∙5H2O = 250g
1 moles of CuSO4∙5H2O= 250 g
X moles of CuSO4∙5H2O = 4.08 g
Hence,
X moles = 0.016346 moles
Step 2: finding volume
0.016346 moles of CuSO4∙5H2O dissolved in = 250cm3
X moles dissolved = 1000cm3
Therefore,
Therefore, option C is the correct answer.
