WCH11 October 2022

15​​ This question is about hydrocarbons obtained from crude oil.

(a) Petrol used in cars has a high proportion of the alkane isooctane. Isooctane can be formed by heating octane to 400°C in the presence of a catalyst.

(i) Give the IUPAC name for isooctane.

(1)

ANSWER

2, 2-dimethyl-4-methylpentane

(ii) Name the industrial process used to convert octane into isooctane.

(1)

ANSWER

Reforming

(iii) Give a reason why petrol needs a high proportion of isooctane.

(1)

ANSWER

The process of reforming converts the straight chain octane into branched/cyclo iso-octane which helps them to burn​​ smoothly in the engine; hence large proportion of iso-octane is needed.

(b) Another way to produce isooctane is by reacting isobutane with 2methylpropene

Draw the skeletal formulae of four isomers of 2methylpropene.

Include only one isomer that does not decolorize bromine water.

(4)

ANSWER

(c) 2methylpropene reacts with hydrogen bromide to form two possible products.

​​ (i) Draw the mechanism for the formation of the major product of the reaction between 2methylpropene and hydrogen bromide, HBr.

​​ Include curly arrows, and relevant lone pairs and dipoles.

(4)

ANSWER

 

(ii) Give the reason why your product in (c) (i) is the major product.

(1)

ANSWER

The tertiary (3o) carbocation is more stable than the primary (1o) carbocation.

(d) Another component of petrol, compound X, contains 92.3% carbon and 7.7% hydrogen by mass.

(i) Calculate the empirical formula of compound X.​​ 

You must show all your working.

(2)

ANSWER

Hence, empirical formula is CH.​​ 

(ii) A sample of compound X has a mass of 0.267g and vaporizes at 85.0°C and 104kPa to produce a gaseous sample with a volume of 98.0cm3

Calculate the molar mass of compound X.​​ 

You must show all your working.

​​ [pV = nRT  ​​ ​​ ​​ ​​ ​​ ​​ ​​ ​​ ​​ ​​ ​​ ​​ ​​ ​​ ​​ ​​ ​​ ​​​​ R = 8.31Jmol–1K–1]

(4)

ANSWER

Step 1: Calculating No. of Moles

n=pVRT

=104000 Pa×98×10-68.31×358

=3.4259×10-3 mol

Step 2: calculating Molecular mass

moles=mass in grammolar mass

molecular mass=0.2673.4259×10-3

molecular mass=78 g

(iii) Deduce the molecular formula of compound X, using your answers to (d)(i) and (d)(ii).

(1)

ANSWER

Identifying the constant

=molecular massempirical formula mass

=7812

=6

Therefore,​​ 

molecular formula=n×empirical formula

=6 ×CH

=C6 H6