WMA11/01 (Edexcel) IAL P1 January 2023, Q8, Quadratics, Inequalities & regions
Figure 2 shows a sketch of the straight line / and the curve C.
Given that l cuts the y-axis at - 12 and cuts the x-axis at 4, as shown in Figure 2,
find an equation for l, writing your answer in the form y = mx + c, where m and c are constants to be found.
(2)
Given that C
has equation y = f(x) where f(x) is a quadratic expression
has a minimum point at (7, -18)
cuts the x-axis at 4 and at k, where k is a constant
deduce the value of k,
(1)
find f(x).
(3)
The region R is shown shaded in Figure 2.
Use inequalities to define R.
(2)
SOLUTION
a- Considering two points on the line to find the gradient of the line, l.
The two points are (0, -12) and (4, 0)
Using the equation of a stright line, where m=3 and c=-12
b- This questions is just of 1 marks, hence, we have to solve by thinking critically.
Here, we may use the fact that the roots of a quadratic equation are symmetrical about the vertex (turning point or critical point). Now, since the the x-cordinate of the vertex is 7, the distance from the vertex to both roots on left and right side of it must be the same. The root x=4 is 3 units to the left of the vertex. Therefore, the other root must also be 3 units to the right of the vertex.
Thus, the other root, k must be
c-
The quadratic equation can be expressed in the form of completing square form as
In this question, the vertex of a quadratic equation is given as (7, -18).
And, on further substituting the x-intercept coordinate (4, 0), the equation becomes
Putting back the value of a in the quadratic equation in the completing square form.
Expanding the brackets.
d-
Since the region is enclosed between the solid lines, the inequalities must be either
Keeping in view the above flash card.
Region is
above/outside the quadratic curve; therefore,
above the straight line; therefore,
rightside of y-axis (x=0)
