WMA11 Jan 2023

  • WMA11/01 (Edexcel) IAL P1 January 2023, Q2, (Straight Line Graphs: Perpendicular Lines​​ &​​ Rectangles)

The points P, Q and R have coordinates (-3, 7), (9, 11) and (12, 2) respectively.

    • Prove that angle PQR 90°

(3)

Given that the point S is such that PQRS forms a rectangle,

    • find the coordinates of S.

(2)

 

SOLUTION

a- ​​ 

For angle PQR to be right angle, the product of their gradients must be equals to -1. Therefore, we will first find the gradients of line PQ and QR.​​ 

It is better to sketch the lines as shown below for better understanding.

Applying the formula of gradient of a line which is​​ 

m=y2-y1x2-x1

mPQ=11-79--3=412=13

mQR=2-1112-9=-93=-3

Check whether their product is equal to -1 or not.

mPQx mQR=13x-3=-1

As the product of lines PQ & QR is equals to -1, the angle PQR is proved to be​​ 90°

b-  ​​​​ 

By looking at the figure, we may see that the horizontal distance between point P and Q is 12. And, the vertical distance between P and Q is 4. Since in a rectangel opposite​​ sides are always equal so the horizontal and vertical distance of S from R or P would be the same. ​​ 

Therefore, the horizontal distance between S & R must be 12 whereas eth vertical distance must be 4.

Hence, the corrdinates of S is (0,2)​​