Trapezium Rule

WMA12/01/IAL(Edexcel)/P2/June 2020/Q2 (The Trapezium Rule)

y =2x5x2+3

• Complete the table below, giving the values of y to 3 decimal places.​​ 

​​ (1)​​ 

(b) Use the trapezium rule, with all the values of y from the completed table, to find an approximate value for​​ 

∫-0.250.752x5x2+3dx

(3)

SOLUTION​​ 

a- Using the following equation​​ 

y =2x5x2+3

For​​ x=0,​​ 

y =2x5x2+3=20502+3

y=0.577

For​​ x=0.5,​​ 

y =2x5x2+3=20.550.52+3

y=0.577

b-​​ 

Using​​ Trapezium Rule to estimate​​ ∫-0.250.752x5x2+3dx.

(The number of trapezium strips are 4 as we know that the number of strip is always 1 less than the total number of values of x and y given.)

h=b-an=0.75-(-0.25)4=14=0.25

A=0.2520.462+0.698+2 0.577+0.653+ 0.686

A=78125

A=0.624 unit2