Area of Shaded Region

Coach Name: Sir Muhammad Abdullah Shah

Edexcel IAL WMA12/01/P2/Oct 2021/Q8 (Differentiation, Integration)

In this question you must show all stages of your working.

Solutions relying entirely on calculator technology are not acceptable.

Figure 2 shows a sketch of part of the curve C with equation​​ 

y =43 x3 - 11x2 + kx                where k is a constant 

The point M is the maximum turning point of C and is shown in Figure 2.​​ 

Given that the x coordinate of M is 2​​ 

  • show that k = 28​​ 

(3)​​ 

  • Determine the range of values of x for which y is increasing.​​ 

(2)​​ 

The line l passes through M and is parallel to the x-axis. The region R, shown shaded in Figure 2, is bounded by the curve C, the line l and the y-axis.​​ 

  • Find, by algebraic integration, the exact area of R.​​ 

(5)

SOLUTION

a- Finding the gradient to the curve at point M, which has x-coordinate 2.

dydx=4x2-22x+k

Since point M is a maximum point on the curve, the gradient to the curve is zero.​​ 

(At stationary points, the gradient of the curve is equal to zero. Therefore, we will diffrentiate the equation of curve and equate the diffrentiated expression to zero. )

dydx= 0

4x2-222+k=0

16-44+k=0

-28+k=0

k=28

b-​​ 

dydx=4x2-22x+28 

To find the range​​ x​​ for which y is increasing,​​ 

dydx>0

4x2-22x+28>0

2x2-11x+14>0

2x2-11x+14>0

x-22x-7>0

We need to mark those ranges of x which are above the x-axis that as the expression is greater than 0. ​​ 

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We can see from the sketch above that the yellow part of the curve are the ones above the x-axis. Hence, the range of values of​​ x​​ for which​​ y​​ is increasing are​​ 

x<2  &  x>3.5

c- ​​ To find the region R, integrate the equation of curve with lower limit 0 and upper limit as 2.​​ 

But the issue is that integration always gives the area bounded between the curve and x-axis. Whereas the area R is above the curve. So, we need to consider the rectangular area as shown in the figure below and subtract from that the area we get from integration of the curve.​​ 

Lets find the y-cordinate of​​ M2, yn

y=4323-11 22+28 2

y=323-44+56

y=683

The area of region R can be found as following​​ 

Area R=Area of Rectangle-Area found by Integration

R=(l×b)-aby.dx

R=683 x 2 -0243 x3-11x2+28xdx

R=1363-4x43x4-11x3+28x2202

R=1363-343-11x33+14x202

R=1363-163-883+56-0

R=403 sq units